0=16+6x-4x^2

Solution for 0=16+6x-4x^2 equation:

0=16+6x-4x^2

We move all terms to the left:

0-(16+6x-4x^2)=0

We add all the numbers together, and all the variables

-(16+6x-4x^2)=0

We get rid of parentheses

4x^2-6x-16=0

a = 4; b = -6; c = -16;
Δ = b2-4ac
Δ = -62-4·4·(-16)
Δ = 292
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{292}=\sqrt{4*73}=\sqrt{4}*\sqrt{73}=2\sqrt{73}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{73}}{2*4}=\frac{6-2\sqrt{73}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{73}}{2*4}=\frac{6+2\sqrt{73}}{8}
$